---
title: "L1-083 谁能进图书馆"
created: 2025-11-28
tags:
  - 算法
---

# L1-083 谁能进图书馆

## 题目 [L1-083 谁能进图书馆](https://pintia.cn/problem-sets/994805046380707840/exam/problems/type/7?problemSetProblemId=1518581226784346112&page=0)

![[image-53d1e6bb.png]]

## 思路分析

## 代码实现

```cpp
#include<bits/stdc++.h>

using namespace std;

#define endl '\n'

using ll = long long;

using ull = unsigned long long;

using PII = pair<int,int>;

using Pll = pair<ll,ll>;

int dx[4]= {-1,0,1,0},dy[4]= {0,1,0,-1};

const int inf = 0x3f3f3f3f;

int main() {

	ios::sync_with_stdio(0),cin.tie(0),cout.tie(0);

	int a,b,c,d;

	cin>>a>>b>>c>>d;

	if (c>=b||d>=b||c>=a) {

		cout<<c<<"-Y";

	} else {

		cout<<c<<"-N";

	}

	cout<<' ';

	if (c>=b||d>=b||d>=a) {

		cout<<d<<"-Y";

	} else {

		cout<<d<<"-N";

	}

	cout<<endl;

	if (c>=a&&d>=a) {

		cout<<"huan ying ru guan";

	} else if (c<a&&d<a) {

		cout<<"zhang da zai lai ba";

	} else if (c<a&&d>=a&&d<b) {

		cout<<"2: huan ying ru guan";

	} else if (d<a&&c>=a&&c<b) {

		cout<<"1: huan ying ru guan";

	} else if (c<a) {

		cout<<"qing 2 zhao gu hao 1";

	} else {

		cout<<"qing 1 zhao gu hao 2";

	}

	return 0;

}
```

## 同类题型

## 视频讲解

---
⬅️ [[L1-082 种钻石|L1-082 种钻石]] 🏠 [[00-天梯赛]] ➡️ [[L1-084 拯救外星人|L1-084 拯救外星人]]